Determining The Equilibrium Constant

Determining the Equilibrium Constant for the Hydrolysis of an Ester Data Collection: | | labor 1 |Trial 2 |Average | |Volume of NaOH employ/cm3 (±0.005cm3)|19.70 |20.00 |19.9 ± 0.2 | |[Flask 4] | | | | |Pipette Solution/10 cm3 (±0.02cm3) |Ethyl ethanoate + make [pic]ethanol + ethanoic acid | |Indicator |Phenophthalein | | Data Processing and Error gracelessness: Flask 4[15cm3 CH3CH2COOCH3 + 13 cm3 H2O + 2cm3 HCl] CH3CH2COOCH3 (l) + H2O (l) [pic] CH3CH2OH (l) + CH3COOH (l) To obtain the Kc expression, the following formula nookie be used: [pic] thence in recite to do so, the tote up theatre number of moles as well as the moles at equaliser atomic number 18 needed.

The initial moles of CH3CH2COOCH3 is: The hesitancy in moles of CH3CH2COOCH3 is: =[pic] [pic] Initial moles of H2 O is : The misgiving in the moles of wat! er is [pic] [pic] but there is also roughly H2O present in the HCl added as a catalyst. This can be calculated by: Mass of HCl= 2.00 x 1.18= 2.36g The hesitancy of the cumulation of HCl [pic] Therefore the mass of HCl is 2.36± 0.006 The moles of HCl is calculated by: The perplexity in the moles HCl: [pic][pic] The moles of H2O is:The uncertainty in the moles of HCl: [pic][pic] Therefore the initial moles of H2O is = 0.722+0.0865= 0.809, the total...If you want to wee-wee a full essay, order it on our website: OrderCustomPaper.com

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